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Find radius of gyration of a rod of length `l` and mass `m` about an axis perpendicular its length through one end. |
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Answer» Here, `K = ?` According to theorem of parallel axes, `I_(end) = I_(cm) + m(l//2)^(2) = (ml^(2))/(12) + (ml^(2))/(4) = (ml^(2))/(3)` `:.mK^(2) = (ml^(2))/(3) or K = (l)/(sqrt(3))` |
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