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A body of moment of inertia `0.5 kg m^(2)` is rotating about a given axis at the rate `1 rps`. What is kinetic energy of rotation of the body about that axis ? |
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Answer» Here, `I = 0.5kg m^(2), n = 1 rps, KE = ?` `KE` of rotation `= (1)/(2) I omega^(2) = (1)/(2)I (2pi n)^(2) = 2pi^(2) n^(2) I = 2 xx (22)/(7) xx (22)/(7) xx 1^(2)xx 0.5 = 9.85 J` |
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