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Find skin depth of 5GHz for silver with a conductivity 6.1×10^7s/m and relative permittivity 1.(a) 0.00091m(b) 0.9113μm(c) 0.319μm(d) 0.1913μmI had been asked this question in a job interview.The above asked question is from Radiation in division Radiation, Baluns & Polarization of Antennas

Answer»

Right option is (b) 0.9113μm

The EXPLANATION: The SKIN depth is given by \(δ = \SQRT{\FRAC{1}{\PI fμσ}}\)

Given f=5GHz

Conductivity σ= 6.1×10^7 s/m

And μr = 1 =>μ=4π ×10^-7

⇨ \(δ = \sqrt{\frac{1}{\pi fμσ}}=0.9113\mu m.\)


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