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| 1. |
Find tan13π/12 |
| Answer» tan(13π/12)\xa0= tan(4π/3 - π/4),= [tan(4π/3) - tan(π/4)]/[1 + tan(4π/3)tan(π/4)]= (-1 + √3)/(1 + √3)\xa0= -(1 - √3)/(1 + √3)\xa0= -(1 - √3)^2/[(1 + √3)(1 - √3)],\xa0= -(1 - √3)^2/(1 - 3)= (1/2)(1 - √3)^2\xa0= (1/2)(1 - 2√3 + 3)\xa0= (1/2)(4 - 2√3)\xa0= 2 - √3. | |