1.

Find the `11^(th)`from the last term (towards the first term) of the AP : `10 , 7, 4, ... , 62.`

Answer» We have
`a = 10, d = (7-10) = -3, l = -62 and n = 11`.
`therefore` 11th term from the end `= {l - (n-1) xx d}`
` = {-62 -(11-1) xx (-3)}`
`= (-62 + 30) = -32.`
Hence, the 11th term from the end of the given AP is -32.


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