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Find the 13^(th) term in the expansion of (8x-(1)/(2sqrt(x)))^(18),xgt0 |
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Answer» Solution :`13^(th)` term in the EXPANSION of `(9x-(1)/(2sqrt(x)))^(18)` is given by `T_(13)=.^(18)C_(12)(9x)^(18-12)(-(1)/(2sqrt(x)))^(12)` `=(18xx17xx16xx15xx14xx13)/(6xx5xx4xx3xx2xx1).9^(6)x^(6)*(1)/(2^(12))*(1)/(x^(6))` `=(2466417681)/(1024)=2408611(17)/(1024)` |
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