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find the 9th term from the end ( towards the first term ) of the A.P.5,9,13......185 |
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Answer» Given A. P is 5 , 9 ,13 , .... 185 Here first term = 5 Common difference = a2 - a1 = 9 -5 = 4 The A.p is 5 , 9 , 13 , ......., 181 , 185 We have find out the 9 th term from the end . Now , rearrange the A. P 185 , 181 , ......, 13 , 9 , 5 First term = a = 185 Common difference = d = a2 - a1 = 181 - 185 = - 4 n th term in an A. P = an = a + ( n - 1 ) d a = 185 ; d = -4 ; n = 9 9 th term = a9 = a + ( 9-1 ) d= 185 + 8 × ( - 4 )= 185 - 32= 153Therefore required 9 th term from the end = 153 |
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