Find the acceleration of center of mass of the blocks of masses m_(1) and m_(2) (m_(1)gt m_(2)) in Atwood's machine :

Find the acceleration of center of mass of the blocks of masses m_(1)

1.	Find the acceleration of center of mass of the blocks of masses m_(1) and m_(2) (m_(1)gt m_(2)) in Atwood's machine :
Answer» Solution :We KNOW from Newton.s laws of motion MAGNITUDE of acceleration of each block is `a=((m_(1)-m_(2))/(m_(1)+m_(2)))g` Now acceleration of their C.M is `a_(cm)=(m_(1)a+m_(2)(-a))/(m_(1)+m_(2))=((m_(1)-m_(2))/(m_(1)+m_(2)))a` `a_(cm)=((m_(1)-m_(2))/(m_(1)+m_(2)))((m_(1)-m_(2))/(m_(1)+m_(2)))g` `therefore` ACCLERATION of centre of MASS `a_(cm)=((m_(1)-m_(2))/(m_(1)+m_(2)))^(2)g`