Find the acceleration of centre of mass of the blocks of masses m_(1) and m_(2) (m_(1)gtm_(2)) in Atwood's machine :

Find the acceleration of centre of mass of the blocks of masses m_(1)

1.	Find the acceleration of centre of mass of the blocks of masses m_(1) and m_(2) (m_(1)gtm_(2)) in Atwood's machine :
Answer» Solution :We know from Newton.s laws of MOTION magnitude of acceleration of each BLOCK is `a=((m_(1)-m_(2))/(m_(1)+m_(2)))G` Now acceleration of their C.M is `a_(cm)=(m_(1)a+m_(2)(-a))/(m_(1)+m_(2))`, `a_(cm)=((m_(1)-m_(2))//(m_(1)+m_(2)))a` `a_(cm)=((m_(1)-m_(2))/(m_(1)+m_(2)))((m_(1)-m_(2))/(m_(1)+m_(2)))g` `:.` ACCLERATION of CENTRE of mass `a_(cm)=((m_(1)-m_(2))/(m_(1)+m_(2)))^(2)g`