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Find the amplitude of the simple harmonic motion obtasined by combining the motions `x_1=(2.0 cm) sinomegat` `and x_2=(2.0cm)sin(omegat+pi/3)` |
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Answer» The two equation given represent simple hormonic motion along the X-ray with amplitudes `A_(1) = 2.0 cm and A_(2) = 2.0 cm`. The phase different between the two simple harmonic motion is `pi//3`. The resultant imple harmonic motion will have an amplitude. A given by `A = sqrt(A_(1)^(2) + A_(2)^(2) + 2A_(1) , A_(2) cosdelta)` `= sqrt ((2.0 cm)^(2) + (2.0 cm)^(2) + 2 (2.0 cm)^(2) cos) (pi)/(3) = 3.5 cm` |
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