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Find the angle between the following pair oflines: `(-x+2)/(-2)=(y-1)/7=(z+3)/(-3)`and `(x+2)/(-1)=(2y-8)/4=(z-5)/4`and check whether the lines areparallel or perpendicular. |
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Answer» The given equations in standard from are `(x-2)/(2)= (y-1)/(7)= (z+3)/(-3) " and " (x+2)/(-1) =(2y-8)/(y-4)/(2)=(z-5)/(4)` Here `a_(1)= 2 ,b_(1)=7 , c_(1)= -3 " and " a_(2)=-1 ,b_(2) =2 ,c_(2) =4` Let `theta ` be the angle between the given lines . Then `" cos " theta = (|a_(1)a_(2)+b_(1)b_(2) +c_(1)c_(2)|)/((sqrt((a_(1)^(2)+b_(1)^(2)+c_(1)^(2))))(sqrt((a_(2)^(2)+b_(2)^(2)+c_(2)^(2)))))` `=(|2xx(-1)+7xx2 +(-3)xx4|)/({sqrt(2^(2)+7^(2)+(-3)^(2)}}{sqrt((-1)^(2)+2^(2)+4^(2))}}` `=(|(-2)+14+(-12)|)/((sqrt(62))(sqrt(21)))=0` `:. theta =(pi)/(2)` Hence the angle between the given lines is `(pi)/(2)` |
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