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Find the angle between the lines barr=3bari-2barj+6bark+lambda(2bari+barj+2bark) and barr=(2barj-5bark)+mu(6bari+3barj+2bark).Hint for solution : Angle between line barr=a_1+lambda barb_1 and r=bara_2+mubarb_2 then angle between them is obtained from cos theta=(|b_1.b_2|)/(|b_1|.|b_2|).

Answer»


ANSWER :`=COS^(-1)((19)/(21))`


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