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Find the angle between the lines vecr = (hati+hatj)+lambda(3hati+2hatj+6hatk) and vecr = (hati-hatk) +mu(hati+2hatj+2hatk) |
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Answer» Solution :Here `VECM = 3hati+2hatj+6hatk` and `vecn=hati+2hatj+2hatk` Let ` theta` be the ANGLE between TWOLINES . `:. cos theta = (vecm.vecn)/(|vecm||vecn|) = ((3hati+2hatj+6hatk).(hati+2hatj+2hatk))/(|3hati+2hatj+6hatk|| hati+2hatj+2hatk|)` `= (3+4+12)/(sqrt(9+4+36)sqrt(1+4+4)) = (19)/(7xx3) = (19)/(21)` `theta = cos^(-1) (19/21)` |
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