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| 1. |
Find the angle between the lines whose direction ratios are proportional to a,b,c and b-c,c-a,a-b,. |
| Answer» Solution :The ANGLE `THETA` between the lines is GIVEN by `costheta=(a(b-C)+b(c-a)+c(a-b))/(sqrt(a^2+b^2+c^2)sqrt((b-c)^2+(c-a)^2+(a-c)^2))` =0 `ifftheta=pi/2` | |