Find the angle between the vectors č -314 J+sk,d -21+ j+2k.

1.	Find the angle between the vectors č -314 J+sk,d -21+ j+2k.
Answer» If the two vectors are given asa⃗a→andb⃗b→then its dot product is expressed as a.b. Suppose these two vectors are separated by angleθθ.To know what's the anglemeasurement we solve with the below formula Cos theta = (-6+4+10)/(√9+25+16)(4+4+1)cos theta= 8/√50*3theeta= cos inverse = 8/3√50

Answer»

If the two vectors are given asa⃗a→andb⃗b→then its dot product is expressed as a.b. Suppose these two vectors are separated by angleθθ.To know what's the anglemeasurement we solve with the below formula

Cos theta = (-6+4+10)/(√9+25+16)(4+4+1)cos theta= 8/√50*3theeta= cos inverse = 8/3√50

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Find the angle between the vectors č -314 J+sk,d -21+ j+2k.

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