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Find the angle between two lines whose directionratios are proportional to `1,1,2a n d(sqrt(3)-1),(-sqrt(3)-1),4`.A. `(pi)/(6)`B. `(pi)/(2)`C. `(pi)/(3)`D. `(pi)/(4)` |
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Answer» Correct Answer - C `" cos " theta = (1xx(sqrt(3)-1)+1xx(-sqrt(3)-1) +2xx4)/({sqrt(1^(2)+1^(2)+2^(2)}}{(sqrt(3)-1)^(2)+(-sqrt(3)-1)^(2)+4^(2)}}` `=((sqrt(3)-1)-sqrt(3)-1+8)/((sqrt(6)xxsqrt(24))) =(sqrt(6))/(sqrt(24)) =(1)/(2) rArr theta =(pi)/(3)` |
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