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Find the angle between two vectors with the help of scalar product . |
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Answer» SOLUTION :If the `theta ` is the angle between `vec(A) and vec(B) ` , then vector product , `vec(A). vec(B) = AB cos theta ` ` :. cos theta = (vec(A).vec(B))/(|vec(A)||vec(B)|)` ` :.cos theta = (vec(A).vec(B))/(AB)` ` :. theta = cos^(-1)((vec(A).vec(B))/(AB))` In CARTESIAN co-ordinate system , `cos theta = ((A_(X)B_(x)+A_(y)B_(y)+A_(Z)B_(z)))/((sqrtA_(x)^(2)+A_(y)^(2)+A_(z)^(2))(sqrt(B_(x)^(2)+B_(y)^(2)+B_(z)^(2))))` |
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