find the angle of a parallelogram ABCD in which ∆A=2∆B

1.	find the angle of a parallelogram ABCD in which ∆A=2∆B
Answer» Given : angle A = 2 angle B We know in parallelogram the adjacent angles have sum 180°. A and B are adjacent angles So, angle A + angle B = 180° 2B + B = 180° 3B = 180 B = 60° A = 2 × 60° = 120° A = C = 120° ( opposite angle of parallelogram) B = D = 60° ( opposite angle of parallelogram)

Answer»

Given : angle A = 2 angle B

We know in parallelogram the adjacent angles have sum 180°.

A and B are adjacent angles

So,

angle A + angle B = 180°

2B + B = 180°

3B = 180

B = 60°

A = 2 × 60° = 120°

A = C = 120° ( opposite angle of parallelogram)

B = D = 60° ( opposite angle of parallelogram)

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