Find the angles of a triangle which are in the ratio 4: 3: 2.

1.	Find the angles of a triangle which are in the ratio 4: 3: 2.
Answer» Let the measures of the given angles of the triangles be (4x)^o, (3x)^oand (2x)^o respectively. Then, = 4x + 3x + 2x = 180^o … [∵sum of the angles of a triangle is 180^o] = 9x = 180^o = x = 180/9 = x = 20 So, the angle measures (4 × 20)^o, (3 × 20)^o, (2 × 20)^o, i.e., 80^o, 60^o, 40^o. Hence, the angles of the triangles are 80^o, 60^o, 40^o.

Answer»

Let the measures of the given angles of the triangles be (4x)^o, (3x)^oand (2x)^o respectively.

Then,

= 4x + 3x + 2x = 180^o … [∵sum of the angles of a triangle is 180^o]

= 9x = 180^o

= x = 180/9

= x = 20

So, the angle measures (4 × 20)^o, (3 × 20)^o, (2 × 20)^o,

i.e., 80^o, 60^o, 40^o.

Hence, the angles of the triangles are 80^o, 60^o, 40^o.

Discussion