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Find the angles which the vector veca = hati-hatj+sqrt2 hatk makes with the coordinates axes. |
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Answer» Solution :`veca` = `hati-hatj+sqrt2 K` `|veca|` = `sqrt(1+1+2)` = 2 `HATA` = `veca/|veca|` = `1/2hat-1/2hatj+1/sqrt2 k` If `ALPHA,beta` and `gamma` are the angles made by `veca`with co-ordinate axes then `COSALPHA` = `1/2,cosbeta` = -1/2 and `cosgamma` = `1/sqrt2` therefore `alpha` = `pi/3,beta` = `2pi/3` and `gamma` = `pi/4` |
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