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Find the area enclosed by y^2=x^3,x=0,y=1 |
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Answer» SOLUTION :Given CURVE is `y^2=x^3` `impliesx=y^(2//3)` It PASS through the origin So the REQUIRED AREA `=int_0^1xdy= int_0^1 y^(2/3)dy=[y^(2/3)/(5//3)]_0^1=3/5` |
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