1.

Find the area enclosed by y^2=x^3,x=0,y=1

Answer»

SOLUTION :Given CURVE is `y^2=x^3`
`impliesx=y^(2//3)`
It PASS through the origin So the REQUIRED AREA
`=int_0^1xdy= int_0^1 y^(2/3)dy=[y^(2/3)/(5//3)]_0^1=3/5`


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