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Find the area of a quadrilateral, whose one of the diagonal is 8 cm and perpendiculars fromthe opposite vertices are 3 cm and 5 cm |
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Answer» Area = (1/2) × diagonal × (sum of perpendiculars) = (1/2) × 8 × (3 + 5) = (1/2) × 8 × 8 = 32cm² |
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