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Find the area of a triangle two sides of which are 18cm and 10cm and the perimeter is42cm. |
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Answer» tell me given:two sides =18cm and 10 cmlet 3rd side be xcmperimeter=42 cm perimeter=18+10+x42=28+xx=42-28x=14cm s=perimeter/2s=42/2s=21 using herons formulaarea of triangle=√s(s-a)(s-b)(s-c)=21(21-18)(21-10)(21-14)=21*3*11*7=4851cm^2 Area is triangle is 4851cm^2 |
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