Find the area of a triangle two sides of which are 18 cm and 10 cm and the perimeter is 42 cm

Find the area of a triangle two sides of which are 18 cm and 10 cm and

1.	Find the area of a triangle two sides of which are 18 cm and 10 cm and the perimeter is 42 cm
Answer» √((21)(21-18)(21-10)(21-14))=69.64 aprox let third side of triangle = x x + 10 + 18 = 42 ( Perimeter of triangle is 42 )x + 28 = 42 ( Transpose of 28 in R.H.S. )x = 42 - 28 x = 14s = 42/2 ; s = 21Area of triangle = √s(s﹣a)(s﹣b)(s﹣c) { Put s = 21, a = 18, b = 14, c = 10 }√ 21(21-18)(21-14)(21-10)√ 2137*11 = √4851 = 69.64 (approx)