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Find the area of an equilateral triangle having each side of length 10 cm. (Take √3 = 1.732) |
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Answer» Given: Side of the equilateral triangle = 10cm Thus we have: Area of the equilateral triangle = \(\frac{\sqrt{3}}{4}\) side2 = \(\frac{\sqrt{3}}4{}\times 10\times 10\) = 25 x 1.732 = 43.3 cm2 |
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