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Find the area of the equilateral ABCD. Here, AC = 22 cm, BM = 3 cm, DN = 3 cm and BM ⊥ AC, DN ⊥ AC. |
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Answer» Here, AC = 22 cm, BM = 3 cm, DN = 3 cm Area of quadrilateral ABCDF = Area of Δ ABC + Area of Δ ADC = 1/2 x AC x BM + 1/2 x AC x DN = 1/2 x 22 x 3 + 1/2 x 22 x 3 = 3 x 11 + 3 x 11 = 33 + 33 = 66 cm2 Thus, the area of quadrilateral ABCD is cm2. |
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