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Find the area of the following quadrilateral.10 cm8 cm8 cm10 cmB6 cmC |
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Answer» Area of APB= Ap= √10^2-8^2= 6now area= 1/2*6*8= 24area if PQBC= 8*6= 48total area= area of PQBC + area of 2 triangle= 48+48= 96cm^2 Area of APB=1/2 *10*8=40sqcm triangle APB is congruent to triangle DQC40sqcm=40sqcmArea of PBQC8*648sqcm Area ofAPQDCB40+40+48=128sqcm |
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