1.

Find the area of the portion of the parabola y^2=4x bounded by the double ordinate through(3,0).

Answer»

Solution :Given parabole is `y^2=4x`.

Area = `2int_0^3 ydx=2 int_0^3 sqrt4xdx`
`=4[X^(3//2)/(3//2)]_0^3=8/3 3^(3//2)=8sqrt3`


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