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| 1. |
Find the area of triangle ,two sides of which are 8cm and 11cm and perimeteris 32cm |
| Answer» Perimeter = a+b+c......32cm= 8cm + 11cm +c....32=19cm+c....32-19=c....13cm=c....Semi perimeter = perimeter/2... =32/2 =16=√s(s-a)(s-b)(s-c)...=√16(16-8)(16-11)(16-13)....=√16(8)(5)(3).. Now,take LCM of all digits..=√2*2*2*2(2*2*2)(5)(3).... Make pair and put them outside...=2*2*2√2*3*5...=4*2√6*5...=8√30cm Is this answer is correct . if no so please comment or report me.I will correct my mistake... ......thank you | |