1.

Find the area under the normal curve with mean 0 and variance 1 that lies between (-1.64) and 1.64.

Answer»

Here z~N(0, 1) 

∴ p[-1 .64 < Z < 1.64] 

= Area from 0 to (-1.64) + area from 0 to 1.64 

∴ From the table = 0.4495 + 0.4495 

= 0.899.



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