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Find the average acceleration in first `20 s`. (Hint: Area under `a-t` fraph is equal to the change in velocity). . |
Answer» Let us first find the charge in velocity Change in velcity is the area under the acceleration=time graph. For first `20 s`, Area `=Delta v (1)/(2) xx10 xx20+10xx20 =300 ms^(-1)` Average acceleration `=(Delta v)/(Delta t) =(300)/(20) =15 ms^(-2)`. |
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