1.

Find the average value of d.c. voltage that can be obtained from the half wave rectifier of Fig. assuming that the diode is ideal one.

Answer» Max. value of the input voltage,`V_(0)=sqrt(2)V_(rms)=sqrt(2)xx200=282.8V` to primary of transformer Max. value of output voltage across secondary of transformer `V_(s)=n_(s)/n_(p)xxV_(p)=1/10xx282.8=28.28V`
d.c. voltage across the load is
`V_(dc)=V_(s)/pi=28.28/3*142=9.0V`


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