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Find the binding energy of `._(26)^(56)Fe`. Atomic mass of Fe is 55.9349u and that of Hydrogen is 1.00783u and mass of neutron is 1.00876u. |
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Answer» Mass of hydrogen atom `m_(p)=1.00876u , m_(n)=1.00867u` `Z=26, A = 56` Mass of Iron atom M = 55.9349u (i) Mass defect `Delta M` `= [Zm_(P)+(A-Z)m_(n)-M]` `=[26xx1.00876+(56-26)(1.00867)-55.9349]u` `therefore Delta m = 0.55296u` (ii) BE of nucleus `= Delta MC^(2)` `= Delta M xx 931.5 MeV` `= 0.55296(931.5) MeV` `= 515.08 MeV` |
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