1.

Find the bond enthalpy of N - H bond in ammonia by using the change in enthalpy for the reaction given below. N_(2(g)) + 3H_(2(g)) to 2NH_(3(g)) ,DeltaH= -23 k.cal Bond energy N-=N= 226, H-H= 103 k.cal

Answer»

SOLUTION :BOND energy N - H = 93 k.cal/mole


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