Find the cartesian equation of the line which passes through the point

1.	Find the cartesian equation of the line which passes through the point (- 2, 4, – 5) and parallel to the line given by \(\frac{x + 3}{3} = \frac{y - 4}{5} = \frac{z + 8}{6}\)
Answer» \(\vec{a} \) = - 2i + 4j - 5k and \(\vec{b} \) = 3i + 5j + 6k equation of a line through (-2, 4, - 5) and is parallel to the vector 3i + 5j + 6k \(\frac{x + 3}{3} = \frac{y - 4}{5} = \frac{z + 5}{6}\)

Find the cartesian equation of the line which passes through the point (- 2, 4, – 5) and parallel to the line given by \(\frac{x + 3}{3} = \frac{y - 4}{5} = \frac{z + 8}{6}\)

Answer»

\(\vec{a} \) = - 2i + 4j - 5k and

\(\vec{b} \) = 3i + 5j + 6k

equation of a line through (-2, 4, - 5)

and is parallel to the vector 3i + 5j + 6k

\(\frac{x + 3}{3} = \frac{y - 4}{5} = \frac{z + 5}{6}\)