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Find the Cartesian equation of the line whichpasses through the point (2, 4, 5) and is parallel to the line `(x+3)/3=(4-y)/5=(z+8)/6dot` |
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Answer» As these two lines are parallel, their direction ratios will be in equal ratios. Equation of the given line is, `(x+3)/3 = (4-y)/5 = (z+8)/6` `=>(x+2)/3 = (y-4)/-5 = (z+5)/6` So,direction ratios of the given line is `(3,-5,6)`. As the line is passing through `(-2,4,-5)` so, equation of the required line will be, `(x+2)/3 = (y-4)/-5 = (z+5)/6` `=>(x+2)/3 = (4-y)/5 = (z+5)/6`, which is the required equation. |
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