Saved Bookmarks
| 1. |
Find the centre and radius of the following circles : a(x^2 + y^2) - bx - cy = 0 |
|
Answer» SOLUTION : `a(x^2 + y^2) - BX - cy = 0` or, `x^2 + y^2 - (bx)a - (cy)/a = 0` `THEREFORE` 2g = -b/a, 2f = -c/a, c = 0 `therefore` g = -b/2a, f = -c/2a `therefore` CENTRE at (-g, -f) = (b/2a, c/2a) and radius = `sqrt(g^2 + f^2 - c) = sqrt((b^2)/(4a^2) + (c^2)/(4a^2))` = `sqrt((b^2 + c^2)/(2a))` |
|