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Find the centre of mass of the system: |
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Answer» Solution :From the figure we can write, `X_(cm) = (m_(0) XX 0 + m_(0) xx L + m_(0) xx L + m_(0) xx 2L)/(m_(0) + m_(0) + m_(0) + m_(0)) rArr X_( cm) = L` `Y_(CM) = (m_(0) xx 0 + m_(0) xx 0 + m_(0) xx L + m_(0) xx 0)/(m_(0) + m_(0) + m_(0) + m_(0)) rArr Y_(cm) = L/4` `therefore` Co-ordinates of CENTRE of mass are `(X_(cm), Y_(cm)) =(L, L/4)` |
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