Find the change in the internal energy of 2 kg of water as it heated from `0^(0)C to 4^(0)C`. The specific heat capacity of water is `4200 J kg^(-1) K^(-1)` and its densities at `0^(0)C` and `4^(0)C` are `999.9 kg m^(-3)` and `1000 kg m^(-3)` respectively. atmospheric pressure `=10^(5)` Pa.

Find the change in the internal energy of 2 kg of water as it heated f

1.	Find the change in the internal energy of 2 kg of water as it heated from `0^(0)C to 4^(0)C`. The specific heat capacity of water is `4200 J kg^(-1) K^(-1)` and its densities at `0^(0)C` and `4^(0)C` are `999.9 kg m^(-3)` and `1000 kg m^(-3)` respectively. atmospheric pressure `=10^(5)` Pa.
Answer» Correct Answer - B::C Given `M = 2kg` `Delta theta = 4^@C s_u = 4200J/kgK.` `p_0 = 999.9kg/m^3` `p_1 = 1000kg/m^3,P = 10^6kpa.` `Let internal energy = Delta V` `DeltaQ = DeltaU+DeltaW` `rArr ms Delta theta = DeltaU+P(V_0-V_4)` `rArr 2xx4200xx4 = delta U+10^2(V_0)-(V_4)` `rArr 33600 = DeltaU+10^5((m)/(p_0)-(m)/(p_4))` `rArr = Delta U +10^5xx0.0000002`ltbr.`rArr 33600 = Delta U +0.02` `Delta U = (33600-0.02)J`

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Find the change in the internal energy of 2 kg of water as it heated from `0^(0)C to 4^(0)C`. The specific heat capacity of water is `4200 J kg^(-1) K^(-1)` and its densities at `0^(0)C` and `4^(0)C` are `999.9 kg m^(-3)` and `1000 kg m^(-3)` respectively. atmospheric pressure `=10^(5)` Pa.

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