Two moles of an ideal monoatomic gas are expanded according to the equation pT=constant form its initial state `(p_0, V_0)` to the final state due to which its pressure becomes half of the initial pressure. The change in internal energy is A. (a) `(3p_0V_0)/(4)`B. (b) `(3p_0V_0)/(2)`C. (c) `(9p_0V_0)/(2)`D. (d) `(5p_0V_0)/(2)`

Two moles of an ideal monoatomic gas are expanded according to the equ

1.	Two moles of an ideal monoatomic gas are expanded according to the equation pT=constant form its initial state `(p_0, V_0)` to the final state due to which its pressure becomes half of the initial pressure. The change in internal energy is A. (a) `(3p_0V_0)/(4)`B. (b) `(3p_0V_0)/(2)`C. (c) `(9p_0V_0)/(2)`D. (d) `(5p_0V_0)/(2)`
Answer» Correct Answer - B Pressure becomes half. So, temperature is doubled. (as `Tprop1/p`) `DeltaU=nC_VDeltaT` `T_i=(p_0V_0)/(nR)` `T_f=(2p_0V_0)/(nR)` `:.` `Delta=T_f-T_i=(p_0V_0)/(nR)` `:.` `DeltaU=n(3/2R)((p_0V_0)/(nR))=(3p_0V_0)/(2)`

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