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Find the co- ordinate of the foot of the perpendicular from the point (-1,3) to the line 3x – 4y – 16 = 0. |
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Answer» Let (a, b) be the coordinates of the foot of perpendicular from the point (- 1,3) to the line and slope of the line joining (-1,3) and (a, b) = ( - 3)/(a + 1) Slope of the line 3x – 4y – 16 = 0 is = 3/4 Since two lines are perpendicular (b - 3)/(a + 1) (3/4) = - 1 4a + 3b = 5 ………….. (1) Point (a b) lies on 3x – 4y – 16 = 0 3a – 4b – 16 = 0 …………. (2) Solving (1) & (2), we get a = 68/25 b = 49/25 |
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