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Find the common factors of the terms(i) 12x, 36(ii) 2y, 22xy(iii) 14pq, 28p2q2 |
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Answer» (i) 12x = 2 × 2 × 3 × x 36 = 2 × 2 × 3 × 3 (ii) 2y = 2 × y 22xy = 2 × 11 × x × y (iii) 14pq = 2 × 7 × p × q 28p2q2 = 2 × 2 × 7 × p × p × q × q The common factors are 2, 7, p, q. And, 2 × 7 × p × q = 14pq |
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