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Find the compound interest on Rs 40,000 at 12% per annum for a period of 2 years. (in Rs).A. 10176B. 8000C. 9176D. 10000 |
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Answer» Correct Answer - A P =Rs 40,000, `R=12%, n=2` `CI=P[(1+R/100)^(n)-1]` `=P[(1+12/100)^(2)-1]` `=40,000[(28/25)^(2)-1]` `=40,000[(28^(2)-25^(2))/(25^(2))]` `=40,000((28+25)*28-25)/(25 xx 25)` `=64 xx 53 xx 3 ="Rs" 10,176` |
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