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Find the condition that one root of ax2 + bx + c = 0 may be four times the other. |
Answer» Let the roots be α and 4α. Then, α + 4α = 5α = \(-\frac{b}{a}\) α . 4α = 4α2 = \(\frac{c}{a}\) From (i) α = \(\frac{b}{5a}\) ∴ From (ii) 4. \(\big(-\frac{b}{5a}\big)^2\) = \(\frac{c}{a}\) ⇒ \(\frac{4b^2}{25a^2}\) = \(\frac{c}{a}\) ⇒ 4b2 = 25ac. |
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