Find the coordinates of points on the parabola `y^2=8x`whose focal dis

1.	Find the coordinates of points on the parabola `y^2=8x`whose focal distance is `4.`
Answer» Given parabola is `y^(2)`=8x On compairing this parabola to the `y^(2)`=4ax, we get…..(i) `8x=4axrArra=2` `therefore` Focal distance=`abs(x+a)=4` `rArr abs(x+2)=4` `rArr x+2=pm4` `rArr x=2,-6` But `xne-6` For x=2, `y^(2)=8xx2` `therefore y^(2)=16rArry=pm4` So, thepoints are (2,4) and (2,-4).

Discussion

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