1.

Find the cost of watering a trapezoidal field whose parallel sides are 10 m and 25 m respectively, the perpendicular distance between them is 15 cm and the rate of watering is 4 rupees per m

Answer»

Considering the distance between parallel sides (h) = 15 mLet one parallelside of the trapezoid be `a` = 10mAnother parallel side be `b` = 25mThe height that is the distance between the parallel sides = 15mArea = [(a+b)/2]h = [(10+25)/2×15] m² = [35/2× 15] m² = [17.5× 15]m² = 262.5 m²Cost of watering one m² area = Rs 4Cost of watering 262.5 m²area = Rs 1050

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can you help me second answer

The area of a Trapezium is 300 m square the perpendicular distance between the two parallel side is 15 M if the difference of The parallel sides is 16 m find the length of the parallel side



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