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| 1. |
Find the critical numbers of the rational polynomial (x^2+1)/(x^2-x-6). |
| Answer» SOLUTION :`(x^2+1)/(x^2-x-6)=((x^2+1))/((x+2)(x-3))` Since the ROOTS of `x^2+1` are non-real, so these are not considerable. But the roots of `x^2-x-6` are (-2,3), which are real. Therefore the critical POINTS are -2 and 3. | |