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Find the cube of:(i) 7/9 (ii) -8/11(iii) 12/7 (iv) -13/8(v) \(2\frac{2}{5}\)(vi) \(3\frac{1}{4}\) |
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Answer» (i) 7/9 (7/9)3 = 73/93 = 343/729 (ii) -8/11 (-8/11)3 = -83/113 = -512/1331 (iii) 12/7 (12/7)3 = 123/73 = 1728/343 (iv) -13/8 (-13/8)3 = -133/83 = -2197/512 (v) \(2\frac{2}{5}\) (12/5)3 = 123/53 = 1728/125 (vi) \(3\frac{1}{4}\) (13/4)3 = 133/43 = 2197/64 |
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