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1. |
Find the degree of (2a2 + 3ab – b2) – (3a2 - ab - 3b2) |
Answer» (2a2 + 3ab – b2) – (3a2 – ab – 3b2) = (2a2 + 3ab – b2) + (- 3a2 + ab + 3b2) = 2a2 + 3ab – b2 – 3a2 + ab + 3b2 = 2a2 – 3a2 + 3ab + ab + 3b2 – b2 = 2a2 – 3a2 + ab (3 + 1) + b2(3 – 1) = – a2 + 4 ab + 2b2 Hence degree of the expression is 2. |
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