Find the depth at which the value of g becomes 25% of that at the surface of the earth. (Radius of the earth = 6400 km)

Find the depth at which the value of g becomes 25% of that at the surf

1.	Find the depth at which the value of g becomes 25% of that at the surface of the earth. (Radius of the earth = 6400 km)
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> at a depth `g_(d) = g(1-(d)/(R))` <br/> In this problem, `g_(d) = (25)/(100)g = 0.25 g` <br/> <a href="https://interviewquestions.tuteehub.com/tag/substituting-1231652" style="font-weight:bold;" target="_blank" title="Click to know more about SUBSTITUTING">SUBSTITUTING</a> `g_(d) = 0.25g` and R = 6400 km <br/> we <a href="https://interviewquestions.tuteehub.com/tag/get-11812" style="font-weight:bold;" target="_blank" title="Click to know more about GET">GET</a> d = 4800 km</body></html>